h8 modems wrote:yeah meant surface area, sorry.
but still I just can't comprehend that.
Take a cube with a side length of x
The volume of the cube, V=x^3
The surface area of the cube, A=6x^3
On one side of the cube draw a square in the center that has a side length of x/2. Extend this square through the length of the cube to get an object of volume
Vo=[(x^2)/4]*x.
Remove this object from the cube. The volume of cube left is now
V-Vo=x^3-(x^3)/4.
But the surface area of the cube has changed to
A=6x^2 - (2x^2)/4 + (4x^2)/2 = 15x^2/2
So you can see that although the volume of the cube has decreased there has been an addition in surface area. Keep subtracting volumes, causing an increase in surface area and you get the idea. Sorry for the lack elegance.
Jon